Optimal. Leaf size=38 \[ 2 a^2 x-\frac {2 i a^2 \log (\cos (c+d x))}{d}-\frac {a^2 \tan (c+d x)}{d} \]
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Rubi [A]
time = 0.01, antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps
used = 2, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {3558, 3556}
\begin {gather*} -\frac {a^2 \tan (c+d x)}{d}-\frac {2 i a^2 \log (\cos (c+d x))}{d}+2 a^2 x \end {gather*}
Antiderivative was successfully verified.
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Rule 3556
Rule 3558
Rubi steps
\begin {align*} \int (a+i a \tan (c+d x))^2 \, dx &=2 a^2 x-\frac {a^2 \tan (c+d x)}{d}+\left (2 i a^2\right ) \int \tan (c+d x) \, dx\\ &=2 a^2 x-\frac {2 i a^2 \log (\cos (c+d x))}{d}-\frac {a^2 \tan (c+d x)}{d}\\ \end {align*}
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Mathematica [B] Both result and optimal contain complex but leaf count is larger than twice
the leaf count of optimal. \(100\) vs. \(2(38)=76\).
time = 0.61, size = 100, normalized size = 2.63 \begin {gather*} -\frac {a^2 \sec (c) \sec (c+d x) \left (4 \text {ArcTan}(\tan (3 c+d x)) \cos (c) \cos (c+d x)-4 d x \cos (2 c+d x)+\cos (d x) \left (-4 d x+i \log \left (\cos ^2(c+d x)\right )\right )+i \cos (2 c+d x) \log \left (\cos ^2(c+d x)\right )+2 \sin (d x)\right )}{2 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.04, size = 40, normalized size = 1.05
method | result | size |
derivativedivides | \(\frac {a^{2} \left (-\tan \left (d x +c \right )+i \ln \left (1+\tan ^{2}\left (d x +c \right )\right )+2 \arctan \left (\tan \left (d x +c \right )\right )\right )}{d}\) | \(40\) |
default | \(\frac {a^{2} \left (-\tan \left (d x +c \right )+i \ln \left (1+\tan ^{2}\left (d x +c \right )\right )+2 \arctan \left (\tan \left (d x +c \right )\right )\right )}{d}\) | \(40\) |
norman | \(2 a^{2} x -\frac {a^{2} \tan \left (d x +c \right )}{d}+\frac {i a^{2} \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{d}\) | \(42\) |
risch | \(-\frac {4 a^{2} c}{d}-\frac {2 i a^{2}}{d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}-\frac {2 i a^{2} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d}\) | \(54\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.49, size = 41, normalized size = 1.08 \begin {gather*} a^{2} x + \frac {{\left (d x + c - \tan \left (d x + c\right )\right )} a^{2}}{d} + \frac {2 i \, a^{2} \log \left (\sec \left (d x + c\right )\right )}{d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.35, size = 56, normalized size = 1.47 \begin {gather*} -\frac {2 \, {\left (i \, a^{2} + {\left (i \, a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} + i \, a^{2}\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right )\right )}}{d e^{\left (2 i \, d x + 2 i \, c\right )} + d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.12, size = 53, normalized size = 1.39 \begin {gather*} - \frac {2 i a^{2}}{d e^{2 i c} e^{2 i d x} + d} - \frac {2 i a^{2} \log {\left (e^{2 i d x} + e^{- 2 i c} \right )}}{d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.51, size = 66, normalized size = 1.74 \begin {gather*} -\frac {2 \, {\left (i \, a^{2} e^{\left (2 i \, d x + 2 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) + i \, a^{2} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) + i \, a^{2}\right )}}{d e^{\left (2 i \, d x + 2 i \, c\right )} + d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 3.23, size = 29, normalized size = 0.76 \begin {gather*} \frac {a^2\,\left (-\mathrm {tan}\left (c+d\,x\right )+\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,2{}\mathrm {i}\right )}{d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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